If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8r^2-128=0
a = 8; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·8·(-128)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*8}=\frac{-64}{16} =-4 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*8}=\frac{64}{16} =4 $
| (3-5y)/4=(2-4y)/3 | | 0=x^2+1.5x-5 | | 4s+15=6s+5 | | 3x+x+5=12 | | 14-8k=-82 | | 12-6a=8a | | 15=3.75x | | 1/3x+6=2/3x-4 | | 21-5x=76 | | 7x-11=5+3x | | 3x+2=5x-6+6 | | 3z=81z= | | 9x+4=-7+2x+25 | | p+20=3p+8 | | 4c+5=3c+4+8c | | 7/32a=3/14 | | x^2+16x-341=0 | | a/8.6+7.2=1.4 | | 4t+3.6=-434 | | -75=6-9f | | y^2+6y+21=0 | | Y/2x+1=4 | | 2x+7-3x=2x-8 | | 5,6x=3,2x+13,2 | | -16x-13=-16x-13 | | Y=-4x158 | | 0.6p=p+32 | | Y+3y+3y+y=0 | | -5=-4x+7(x-2) | | -15=6w+3(w+4) | | -16+25x^2=0 | | 22-4v=18 |